$$ \frac{9}{10} + \frac{4}{9} \cdot (2 \frac{1}{21} - 1\frac{1}{3}) - \frac{2}{3} = \frac{9}{10} + \frac{4}{9} \cdot (\frac{43}{21} - \frac{4}{3}) - \frac{2}{3} = \frac{9}{10} + \frac{4}{9} \cdot (\frac{43}{21} - \frac{28}{21}) - \frac{2}{3} = $$ $$ = \frac{9}{10} + \frac{4}{9} \cdot \frac{15}{21} - \frac{2}{3} = \frac{9}{10} + \frac{4 \cdot 15}{9 \cdot 21} - \frac{2}{3} = \frac{9}{10} + \frac{60}{189} - \frac{2}{3} = \frac{9}{10} + \frac{20}{63} - \frac{2}{3} = $$ $$ = \frac{9 \cdot 63}{10 \cdot 63} + \frac{20 \cdot 10}{63 \cdot 10} - \frac{2 \cdot 210}{3 \cdot 210} = \frac{567}{630} + \frac{200}{630} - \frac{420}{630} = \frac{567 + 200 - 420}{630} = \frac{347}{630} $$
Ответ: $$\frac{347}{630}$$