Решение:
Линейная функция имеет вид $$y = kx + b$$, где k и b - коэффициенты.
- $$y = 2x - 2$$, $$k = 2$$, $$b = -2$$
- $$y = 2x + 2$$, $$k = 2$$, $$b = 2$$
- $$y = 3x - 1$$, $$k = 3$$, $$b = -1$$
- $$y = 3x + 4$$, $$k = 3$$, $$b = 4$$
- $$y = 2 + x = x + 2$$, $$k = 1$$, $$b = 2$$
- $$y = -2 - x = -x - 2$$, $$k = -1$$, $$b = -2$$
- $$y = -2x + 1$$, $$k = -2$$, $$b = 1$$
- $$y = 5 - x = -x + 5$$, $$k = -1$$, $$b = 5$$
- $$y = 3 + x = x + 3$$, $$k = 1$$, $$b = 3$$
- $$y = -3 + x = x - 3$$, $$k = 1$$, $$b = -3$$
- $$y = -x - 3$$, $$k = -1$$, $$b = -3$$
- $$y = -2x - 5$$, $$k = -2$$, $$b = -5$$
- $$y = -3x + 2$$, $$k = -3$$, $$b = 2$$
- $$y = -3x + 4$$, $$k = -3$$, $$b = 4$$
- $$y = -2 + 4x = 4x - 2$$, $$k = 4$$, $$b = -2$$
- $$y = 0.5x - 2$$, $$k = 0.5$$, $$b = -2$$
- $$y = 0.5x + 2$$, $$k = 0.5$$, $$b = 2$$
- $$y = 0.5x - 5$$, $$k = 0.5$$, $$b = -5$$
- $$y = -0.5x + 4$$, $$k = -0.5$$, $$b = 4$$
- $$y = 1 - 5x = -5x + 1$$, $$k = -5$$, $$b = 1$$
- $$y = \frac{1}{3}x - 1$$, $$k = \frac{1}{3}$$, $$b = -1$$
- $$y = \frac{1}{3}x + 3$$, $$k = \frac{1}{3}$$, $$b = 3$$
- $$y = -\frac{1}{3}x - 2$$, $$k = -\frac{1}{3}$$, $$b = -2$$
- $$y = -\frac{1}{3}x + 1$$, $$k = -\frac{1}{3}$$, $$b = 1$$
- $$y = 2 - \frac{x}{5} = -\frac{1}{5}x + 2$$, $$k = -\frac{1}{5}$$, $$b = 2$$
- $$y = \frac{1}{5}x - 2$$, $$k = \frac{1}{5}$$, $$b = -2$$
- $$y = -\frac{1}{4}x + 2$$, $$k = -\frac{1}{4}$$, $$b = 2$$
- $$y = \frac{x}{4} - 1 = \frac{1}{4}x - 1$$, $$k = \frac{1}{4}$$, $$b = -1$$
- $$y = \frac{x}{5} + 4 = \frac{1}{5}x + 4$$, $$k = \frac{1}{5}$$, $$b = 4$$
- $$y = -1 + \frac{x}{6} = \frac{1}{6}x - 1$$, $$k = \frac{1}{6}$$, $$b = -1$$
Ответ: см. решение