Ответ:
Приводим дробные части к общему знаменателю и выполняем действия с целыми и дробными частями.
- \(6-2\frac{7}{8}=3\frac{1}{8}\).
- \(5\frac{1}{3}+2\frac{3}{15}=7+\frac{5}{15}+\frac{3}{15}=7\frac{8}{15}\).
- \(9\frac{5}{6}-3=6\frac{5}{6}\).
- \(7\frac{1}{4}-3\frac{3}{5}=6\frac{5}{4}-3\frac{3}{5}=3\frac{13}{20}\).
- \(2\frac{8}{14}+6\frac{18}{21}=8+\frac{4}{7}+\frac{6}{7}=9\frac{3}{7}\). Исправление: \(\frac{4}{7}+\frac{6}{7}=1\frac{3}{7}\), поэтому ответ \(9\frac{3}{7}\).
- \(10-4\frac{2}{5}=5\frac{3}{5}\).
- \(8\frac{1}{9}-5\frac{5}{6}=7\frac{10}{9}-5\frac{5}{6}=2\frac{5}{18}\).
- \(1\frac{3}{10}+3\frac{2}{5}=4\frac{7}{10}\).
- \(9\frac{1}{3}-5\frac{2}{7}=4+\frac{7}{21}-\frac{6}{21}=4\frac{1}{21}\).
- \(4\frac{2}{3}-1\frac{1}{6}=3\frac{1}{2}\).
- \(6\frac{2}{7}+10=16\frac{2}{7}\).
- \(7\frac{11}{16}+2\frac{13}{24}=9+\frac{33}{48}+\frac{26}{48}=10\frac{11}{48}\).
- \(12-5\frac{13}{18}=6\frac{5}{18}\).
- \(10\frac{18}{25}-8=2\frac{18}{25}\).
- \(8\frac{11}{20}+5\frac{13}{24}=13+\frac{66}{120}+\frac{65}{120}=14\frac{11}{120}\).
- \(9\frac{17}{24}-7=2\frac{17}{24}\).
- \(9-7\frac{18}{20}=1\frac{1}{10}\).
- \(12\frac{3}{7}+4\frac{11}{9}=16+\frac{27}{63}+\frac{77}{63}=17\frac{41}{63}\).
- \(6\frac{11}{20}+4\frac{7}{15}=10+\frac{33}{60}+\frac{28}{60}=11\frac{1}{60}\).
- \(5\frac{13}{16}+3=8\frac{13}{16}\).
- \(10\frac{1}{18}-4\frac{2}{3}=9\frac{19}{18}-4\frac{12}{18}=5\frac{7}{18}\).
- \(8-1\frac{5}{6}=6\frac{1}{6}\).
- \(7\frac{12}{16}-4=3\frac{3}{4}\).
- \(2\frac{5}{6}+1\frac{3}{4}=3+\frac{10}{12}+\frac{9}{12}=4\frac{7}{12}\).
