Ответ:

Приводим дробные части к общему знаменателю и выполняем действия с целыми и дробными частями.

  1. \(6-2\frac{7}{8}=3\frac{1}{8}\).
  2. \(5\frac{1}{3}+2\frac{3}{15}=7+\frac{5}{15}+\frac{3}{15}=7\frac{8}{15}\).
  3. \(9\frac{5}{6}-3=6\frac{5}{6}\).
  4. \(7\frac{1}{4}-3\frac{3}{5}=6\frac{5}{4}-3\frac{3}{5}=3\frac{13}{20}\).
  5. \(2\frac{8}{14}+6\frac{18}{21}=8+\frac{4}{7}+\frac{6}{7}=9\frac{3}{7}\). Исправление: \(\frac{4}{7}+\frac{6}{7}=1\frac{3}{7}\), поэтому ответ \(9\frac{3}{7}\).
  6. \(10-4\frac{2}{5}=5\frac{3}{5}\).
  7. \(8\frac{1}{9}-5\frac{5}{6}=7\frac{10}{9}-5\frac{5}{6}=2\frac{5}{18}\).
  8. \(1\frac{3}{10}+3\frac{2}{5}=4\frac{7}{10}\).
  9. \(9\frac{1}{3}-5\frac{2}{7}=4+\frac{7}{21}-\frac{6}{21}=4\frac{1}{21}\).
  10. \(4\frac{2}{3}-1\frac{1}{6}=3\frac{1}{2}\).
  11. \(6\frac{2}{7}+10=16\frac{2}{7}\).
  12. \(7\frac{11}{16}+2\frac{13}{24}=9+\frac{33}{48}+\frac{26}{48}=10\frac{11}{48}\).
  13. \(12-5\frac{13}{18}=6\frac{5}{18}\).
  14. \(10\frac{18}{25}-8=2\frac{18}{25}\).
  15. \(8\frac{11}{20}+5\frac{13}{24}=13+\frac{66}{120}+\frac{65}{120}=14\frac{11}{120}\).
  16. \(9\frac{17}{24}-7=2\frac{17}{24}\).
  17. \(9-7\frac{18}{20}=1\frac{1}{10}\).
  18. \(12\frac{3}{7}+4\frac{11}{9}=16+\frac{27}{63}+\frac{77}{63}=17\frac{41}{63}\).
  19. \(6\frac{11}{20}+4\frac{7}{15}=10+\frac{33}{60}+\frac{28}{60}=11\frac{1}{60}\).
  20. \(5\frac{13}{16}+3=8\frac{13}{16}\).
  21. \(10\frac{1}{18}-4\frac{2}{3}=9\frac{19}{18}-4\frac{12}{18}=5\frac{7}{18}\).
  22. \(8-1\frac{5}{6}=6\frac{1}{6}\).
  23. \(7\frac{12}{16}-4=3\frac{3}{4}\).
  24. \(2\frac{5}{6}+1\frac{3}{4}=3+\frac{10}{12}+\frac{9}{12}=4\frac{7}{12}\).