Let $$P_b$$ be the power of the white kettle and $$P_s$$ be the power of the blue kettle. Let $$t_b$$ be the time for the white kettle to boil and $$t_s$$ be the time for the blue kettle to boil. The amount of heat required to boil the water is the same for both kettles. Thus, $$Q = P_b imes t_b = P_s imes t_s$$. We are given $$P_b = 800$$ W, $$t_b = 8$$ minutes, and $$t_s = 4$$ minutes. We need to find $$P_s$$. Substituting the given values, we have $$800 ext{ W} imes 8 ext{ min} = P_s imes 4 ext{ min}$$. Solving for $$P_s$$, we get $$P_s = (800 ext{ W} imes 8 ext{ min}) / 4 ext{ min} = 1600$$ W.