−1,2 ⋅ 3a = −3,6a
−0,8x ⋅ (−0,7) = 0,56x
−5b ⋅ 2,4c = −12bc
−6a ⋅ 0,7b ⋅ (−0,5c) = 2,1abc
\[-\frac{4}{15}x \cdot \frac{5}{16} \cdot (-y) = \frac{4 \cdot 5}{15 \cdot 16}xy = \frac{20}{240}xy = \frac{1}{12}xy\]
\[1\frac{3}{5}x \cdot (-\frac{15}{32}y) = \frac{8}{5}x \cdot (-\frac{15}{32}y) = -\frac{8 \cdot 15}{5 \cdot 32}xy = -\frac{120}{160}xy = -\frac{3}{4}xy\]
Ответ: 1) -3,6a; 2) 0,56x; 3) -12bc; 4) 2,1abc; 5) 1/12xy; 6) -3/4xy