-14,3 ⋅ 0,6 + 5,7 ⋅ (-1,4) = -8,58 - 7,98 = -16,56
(3,4 - 5) ⋅ (-4,12 + 4,04) = (-1,6) ⋅ (-0,08) = 0,128
\[ \frac{5}{9} \cdot (-\frac{36}{7}) - (-\frac{35}{7}) \cdot \frac{3}{52} = \frac{5}{9} \cdot (-\frac{36}{7}) + \frac{35}{7} \cdot \frac{3}{52} = \] \[ = -\frac{5 \cdot 36}{9 \cdot 7} + \frac{35 \cdot 3}{7 \cdot 52} = -\frac{5 \cdot 4}{1 \cdot 7} + \frac{5 \cdot 3}{1 \cdot 52} = -\frac{20}{7} + \frac{15}{52} = \frac{-20 \cdot 52 + 15 \cdot 7}{7 \cdot 52} = \frac{-1040 + 105}{364} = \frac{-935}{364} = -2 \frac{207}{364} \]
\[ (2 \frac{1}{3} - 3 \frac{1}{4}) \cdot (2 \frac{3}{4} - 0,95) = (\frac{7}{3} - \frac{13}{4}) \cdot (\frac{11}{4} - 0,95) = (\frac{28 - 39}{12}) \cdot (\frac{11}{4} - \frac{95}{100}) = \] \[ = (\frac{-11}{12}) \cdot (\frac{11}{4} - \frac{19}{20}) = (\frac{-11}{12}) \cdot (\frac{55 - 19}{20}) = (\frac{-11}{12}) \cdot (\frac{36}{20}) = -\frac{11 \cdot 36}{12 \cdot 20} = -\frac{11 \cdot 3}{1 \cdot 20} = -\frac{33}{20} = -1 \frac{13}{20} \]
x + 3 = 0 или x - 4 = 0
x = -3 или x = 4
Ответ: x = -3, x = 4
x = 0 или x + 4,3 = 0 или 1,8 - x = 0
x = 0 или x = -4,3 или x = 1,8
Ответ: x = 0, x = -4,3, x = 1,8
Ответ: См. решения выше