Ответ:3. ³√3x/y² : ⁴√y/9x² = (3x/y²)¹/³ : (y/9x²)¹/⁴ = (3x)⁴/¹²y⁻⁸/¹² : y⁴/¹²(9x²)⁻³/¹² = ¹²√(81x⁴y⁻⁸) / ¹²√(y⁴(729x⁶)⁻¹) = ¹²√(81x⁴y⁻⁸ / (y⁴/729x⁶)) = ¹²√(81x⁴y⁻⁸ · 729x⁶/y⁴) = ¹²√59049x¹⁰y⁻¹².