3) $$\left(\frac{x^{5}}{4y^{6}}\right)^{4}:\left(-\frac{x^{6}}{8y^{5}}\right)^{3}=\frac{x^{20}}{4^{4}y^{24}} : \left( -\frac{x^{18}}{8^{3}y^{15}} \right) =\frac{x^{20}}{256y^{24}} \cdot \left( -\frac{512y^{15}}{x^{18}} \right) = -\frac{512}{256} \cdot \frac{x^{20}}{x^{18}} \cdot \frac{y^{15}}{y^{24}}=-2\cdot x^{2} \cdot \frac{1}{y^{9}}=-\frac{2x^{2}}{y^{9}}$$
Ответ: $$\frac{-2x^{2}}{y^{9}}$$