$$6 \frac{3}{4}x - x + 3 \frac{5}{12}x = (6 \frac{3}{4} - 1 + 3 \frac{5}{12})x = (6 \frac{9}{12} - 1 + 3 \frac{5}{12})x = (5 \frac{9}{12} + 3 \frac{5}{12})x = 8 \frac{14}{12}x = 9 \frac{2}{12}x = 9 \frac{1}{6}x$$.
При $$x = 1 \frac{7}{11}$$ имеем:
$$9 \frac{1}{6} \cdot 1 \frac{7}{11} = \frac{9 \cdot 6 + 1}{6} \cdot \frac{1 \cdot 11 + 7}{11} = \frac{55}{6} \cdot \frac{18}{11} = \frac{55 \cdot 18}{6 \cdot 11} = \frac{5 \cdot 11 \cdot 3 \cdot 6}{6 \cdot 11} = 5 \cdot 3 = 15$$.
Ответ: 15