$$6 \frac{3}{4}x - x + 3 \frac{5}{12}x$$
$$= (6 \frac{3}{4} - 1 + 3 \frac{5}{12})x$$
$$= (5 \frac{3}{4} + 3 \frac{5}{12})x$$
$$= (5 \frac{3 \cdot 3}{4 \cdot 3} + 3 \frac{5}{12})x$$
$$= (5 \frac{9}{12} + 3 \frac{5}{12})x$$
$$= 8 \frac{14}{12} x$$
$$= 8 \frac{7}{6} x$$
$$= 9 \frac{1}{6} x$$
$$= \frac{9 \cdot 6 + 1}{6}x$$
$$= \frac{55}{6}x$$
Если $$x = 1 \frac{7}{11}$$, то $$= \frac{55}{6} \cdot 1 \frac{7}{11}$$.
$$= \frac{55}{6} \cdot \frac{1 \cdot 11 + 7}{11}$$
$$= \frac{55}{6} \cdot \frac{18}{11}$$
$$= \frac{5 \cdot 3}{1 \cdot 1}$$
$$= 15$$.
Ответ: $$15$$