\[1^{\backslash\text{(}3x + 1)²} - \frac{3x - 1}{9x^{2} + 6x + 1} - \frac{3x^{\backslash 3x + 1}}{3x + 1} =\]
\[= \frac{9x^{2} + 6x + 1 - 3x + 1 - 9x^{2} - 3x}{(3x + 1)^{2}} =\]
\[= \frac{2}{(3x + 1)^{2}}.\]