Вопрос:

Ответ:

\[= \frac{- 3y + 6}{2y - 3} - \frac{y}{2y - 3} =\]

\[= \frac{- 3y + 6 - y}{2y - 3} = \frac{- 4y + 6}{2y - 3} =\]

\[= \frac{- 2 \cdot (2y - 3)}{2y - 3} = - 2.\]

\[Дополнительное\ решение:\]

\[2y^{2} - 15y + 18 = 0\]

\[y_{1} + y_{2} = 7,5\]

\[y_{1} \cdot y_{2} = 9\]

\[\Longrightarrow y_{1} = 6;\ \ y_{2} = 1,5.\]

\[2y^{2} - 15y + 18 =\]

\[= 2 \cdot (y - 6)(y - 1,5) =\]

\[= (y - 6)(2y - 3).\]