\[4^{{\backslash(x + 1)}^{2}} - \frac{4x - 5}{x^{2} + 2x + 1} - \frac{4x^{\backslash x + 1}}{x + 1} =\]
\[= \frac{4x^{2} + 8x + 4 - 4x + 5 - 4x^{2} - 4x}{(x + 1)^{2}} =\]
\[= \frac{9}{(x + 1)^{2}}.\]