Решение:
$$4b + \frac{3a-20b^2}{5b} = \frac{4b \cdot 5b}{5b} + \frac{3a-20b^2}{5b} = \frac{20b^2+3a-20b^2}{5b} = \frac{3a}{5b}$$
При a = 7, b = -0.2:
$$\frac{3a}{5b} = \frac{3 \cdot 7}{5 \cdot (-0.2)} = \frac{21}{-1} = -21$$
Ответ: -21