$$\frac{3}{4}n + \frac{2}{3} - \frac{4}{18}n$$ при $$n=1\frac{13}{23}$$
$$\frac{3}{4}n + \frac{2}{3} - \frac{2}{9}n = (\frac{3}{4} - \frac{2}{9})n + \frac{2}{3} = (\frac{27}{36} - \frac{8}{36})n + \frac{2}{3} = \frac{19}{36}n + \frac{2}{3}$$
$$\frac{19}{36} \cdot 1\frac{13}{23} + \frac{2}{3} = \frac{19}{36} \cdot \frac{36}{23} + \frac{2}{3} = \frac{19}{23} + \frac{2}{3} = \frac{19 \cdot 3 + 2 \cdot 23}{69} = \frac{57 + 46}{69} = \frac{103}{69} = 1\frac{34}{69}$$
Ответ: $$1\frac{34}{69}$$