$$c - \frac{5}{9}c + 4\frac{5}{6}c = \frac{9}{9}c - \frac{5}{9}c + \frac{4\cdot6+5}{6}c = \frac{9-5}{9}c + \frac{24+5}{6}c = \frac{4}{9}c + \frac{29}{6}c = \frac{4}{9}c^{\frac{x2}{x2}} + \frac{29}{6}c^{\frac{x3}{x3}} = \frac{8}{18}c + \frac{87}{18}c = \frac{8+87}{18}c = \frac{95}{18}c$$
при c=7$$\frac{95}{18} \cdot 7 = \frac{95 \cdot 7}{18} = \frac{665}{18} = 36\frac{17}{18}$$
Ответ: $$36\frac{17}{18}$$