$$\frac{5}{9}c + 4\frac{5}{6}c - c = \frac{5}{9}c + \frac{29}{6}c - c = (\frac{5}{9} + \frac{29}{6} - 1)c = (\frac{5 \cdot 2}{9 \cdot 2} + \frac{29 \cdot 3}{6 \cdot 3} - \frac{18}{18})c = (\frac{10}{18} + \frac{87}{18} - \frac{18}{18})c = (\frac{10+87-18}{18})c = \frac{79}{18}c$$
Подставим $$c = 7\frac{1}{3} = \frac{22}{3}$$
$$\frac{79}{18}c = \frac{79}{18} \cdot \frac{22}{3} = \frac{79 \cdot 22}{18 \cdot 3} = \frac{79 \cdot 11 \cdot 2}{9 \cdot 2 \cdot 3} = \frac{79 \cdot 11}{9 \cdot 3} = \frac{869}{27} = 32\frac{5}{27}$$
Ответ: $$\frac{79}{18}c = 32\frac{5}{27}$$