2. Упростите выражение: 1) 2)3x x-4 x-3 x+3 * 2x-8 x2+3x² x+3 6x * 96 x-3. 9-x2

1) $$ \frac{3x}{x+3} * \frac{96}{2x-8} = \frac{3x*96}{(x+3)*2(x-4)} = \frac{144x}{(x+3)(x-4)}$$ 2) $$ (\frac{x-3}{x-4} - \frac{x+3}{x+3}) : \frac{x-3}{9-x^2} = (\frac{x-3}{x-4} - 1) : \frac{x-3}{9-x^2} = (\frac{x-3-x+4}{x-4}) * \frac{9-x^2}{x-3} = \frac{9-x^2}{(x-4)(x-3)} = - \frac{(x-3)(x+3)}{(x-4)(x-3)} = - \frac{x+3}{x-4} $$ Ответ: 1) $$ \frac{144x}{(x+3)(x-4)} $$, 2) $$- \frac{x+3}{x-4} $$