Ответ:\(a+b-\frac{a-3}{3}=a+b-\frac a3+1=\frac{2a}{3}+b+1\).\(\frac{2b^2-1}{b}-b+5=2b-\frac1b-b+5=b+5-\frac1b\), при \(b\ne0\).\(4a-\frac{a-1}{4}=\frac{16a-a+1}{4}=\frac{15a+1}{4}\).