Представляем одну целую единицу в виде неправильной дроби с тем же знаменателем и складываем с дробной частью:
- \(2\frac{3}{8}=1+\frac{8}{8}+\frac{3}{8}=1\frac{11}{8}\);
- \(3\frac{5}{9}=2+\frac{9}{9}+\frac{5}{9}=2\frac{14}{9}\);
- \(4\frac{1}{11}=3+\frac{11}{11}+\frac{1}{11}=3\frac{12}{11}\);
- \(5\frac{7}{10}=4+\frac{10}{10}+\frac{7}{10}=4\frac{17}{10}\);
- \(3\frac{2}{3}=2+\frac{3}{3}+\frac{2}{3}=2\frac{5}{3}\);
- \(6\frac{1}{6}=5+\frac{6}{6}+\frac{1}{6}=5\frac{7}{6}\);
- \(10\frac{4}{13}=9+\frac{13}{13}+\frac{4}{13}=9\frac{17}{13}\);
- \(4\frac{5}{12}=3+\frac{12}{12}+\frac{5}{12}=3\frac{17}{12}\);
- \(1\frac{11}{100}=0+\frac{100}{100}+\frac{11}{100}=\frac{111}{100}\);
- \(2\frac{3}{13}=1+\frac{13}{13}+\frac{3}{13}=1\frac{16}{13}\);
- \(13\frac{3}{5}=12+\frac{5}{5}+\frac{3}{5}=12\frac{8}{5}\);
- \(11\frac{1}{7}=10+\frac{7}{7}+\frac{1}{7}=10\frac{8}{7}\);
- \(8\frac{10}{21}=7+\frac{21}{21}+\frac{10}{21}=7\frac{31}{21}\);
- \(11\frac{1}{5}=10+\frac{5}{5}+\frac{1}{5}=10\frac{6}{5}\);
- \(5\frac{11}{14}=4+\frac{14}{14}+\frac{11}{14}=4\frac{25}{14}\);
- \(3\frac{17}{25}=2+\frac{25}{25}+\frac{17}{25}=2\frac{42}{25}\);
- \(16\frac{9}{10}=15+\frac{10}{10}+\frac{9}{10}=15\frac{19}{10}\);
- \(20\frac{4}{51}=19+\frac{51}{51}+\frac{4}{51}=19\frac{55}{51}\).
Ответ: \(1\frac{11}{8};\ 2\frac{14}{9};\ 3\frac{12}{11};\ 4\frac{17}{10};\ 2\frac{5}{3};\ 5\frac{7}{6};\ 9\frac{17}{13};\ 3\frac{17}{12};\ \frac{111}{100};\ 1\frac{16}{13};\ 12\frac{8}{5};\ 10\frac{8}{7};\ 7\frac{31}{21};\ 10\frac{6}{5};\ 4\frac{25}{14};\ 2\frac{42}{25};\ 15\frac{19}{10};\ 19\frac{55}{51}\).