в) $\left(-\frac{3}{4}-0,25\right)\cdot\frac{3}{4}\cdot1\frac{1}{3}+\frac{2}{15}$

Question

Вопрос: $Фото задания: в) $\left(-\frac{3}{4}-0,25\right)\cdot\frac{3}{4}\cdot1\frac{1}{3}+\frac{2}{15}$$ Фото задания

Accepted Answer

$0,25=\frac{1}{4}$, а $1\frac{1}{3}=\frac{4}{3}$.

\[\left(-\frac{3}{4}-\frac{1}{4}\right)\cdot\frac{3}{4}\cdot\frac{4}{3}+\frac{2}{15}\]

\[=(-1)\cdot\frac{3}{4}\cdot\frac{4}{3}+\frac{2}{15}=-1+\frac{2}{15}=-\frac{13}{15}\]

Ответ: $-\frac{13}{15}$.

в) \(\left(-\frac{3}{4}-0,25\right)\cdot\frac{3}{4}\cdot1\frac{1}{3}+\frac{2}{15}\)