Решим примеры:
- 26$$\frac{19}{25}$$+35$$\frac{1}{25}$$ = (26+35)+($$\frac{19}{25}$$+$$\frac{1}{25}$$)=61+$$\frac{20}{25}$$=61$$\frac{4}{5}$$
- 19$$\frac{6}{17}$$ + 29 = (19+29)+$$\frac{6}{17}$$=48$$\frac{6}{17}$$
- 203$$\frac{19}{41}$$-40$$\frac{6}{41}$$=(203-40)+($$\frac{19}{41}$$-$$\frac{6}{41}$$)=163+$$\frac{13}{41}$$=163$$\frac{13}{41}$$
- 7$$\frac{7}{8}$$+59$$\frac{7}{8}$$=(7+59)+($$\frac{7}{8}$$+$$\frac{7}{8}$$)=66+$$\frac{14}{8}$$=66+1$$\frac{6}{8}$$=67$$\frac{3}{4}$$
- 35$$\frac{10}{13}$$-25$$\frac{12}{13}$$=(35-25)+($$\frac{10}{13}$$-$$\frac{12}{13}$$)=10-$$\frac{2}{13}$$=9$$\frac{11}{13}$$
- 506$$\frac{9}{13}$$-72=(506-72)+$$\frac{9}{13}$$=434$$\frac{9}{13}$$
- 29-18$$\frac{27}{30}$$=29-18$$\frac{9}{10}$$=(29-18)-$$\frac{9}{10}$$=11-$$\frac{9}{10}$$=10$$\frac{1}{10}$$
- 19$$\frac{13}{149}$$-16=(19-16)+$$\frac{13}{149}$$=3$$\frac{13}{149}$$
- 4$$\frac{4}{15}$$-1$$\frac{9}{15}$$=(4-1)+($$\frac{4}{15}$$-$$\frac{9}{15}$$)=3-$$\frac{5}{15}$$=3-$$\frac{1}{3}$$=2$$\frac{2}{3}$$
- 8$$\frac{6}{23}$$-3=(8-3)+$$\frac{6}{23}$$=5$$\frac{6}{23}$$
- 6-1$$\frac{5}{7}$$=(6-1)-$$\frac{5}{7}$$=5-$$\frac{5}{7}$$=4$$\frac{2}{7}$$
- 1$$\frac{13}{15}$$-1$$\frac{2}{15}$$=(1-1)+($$\frac{13}{15}$$-$$\frac{2}{15}$$)=0+$$\frac{11}{15}$$=\frac{11}{15}$$
- 28$$\frac{7}{20}$$-7=(28-7)+$$\frac{7}{20}$$=21$$\frac{7}{20}$$
- 8$$\frac{2}{44}$$-1$$\frac{7}{44}$$=(8-1)+($$\frac{2}{44}$$-$$\frac{7}{44}$$)=7-$$\frac{5}{44}$$=6$$\frac{39}{44}$$
- 18$$\frac{2}{14}$$-13$$\frac{7}{14}$$=(18-13)+($$\frac{2}{14}$$-$$\frac{7}{14}$$)=5-$$\frac{5}{14}$$=4$$\frac{9}{14}$$
Ответ: 1) 61$$\frac{4}{5}$$, 2) 48$$\frac{6}{17}$$, 3) 163$$\frac{13}{41}$$, 4) 67$$\frac{3}{4}$$, 5) 9$$\frac{11}{13}$$, 6) 434$$\frac{9}{13}$$, 7) 10$$\frac{1}{10}$$, 8) 3$$\frac{13}{149}$$, 9) 2$$\frac{2}{3}$$, 10) 5$$\frac{6}{23}$$, 11) 4$$\frac{2}{7}$$, 12) $$\frac{11}{15}$$, 13) 21$$\frac{7}{20}$$, 14) 6$$\frac{39}{44}$$, 15) 4$$\frac{9}{14}$$