-2,1 ⋅ 4b = -8,4b
-0,7y ⋅ (-0,5) = 0,35y
-4c ⋅ 3,6d = -14,4cd
-5a ⋅ (-0,6b) ⋅ 0,3c = 3ab ⋅ 0,3c = 0,9abc
-\frac{3}{14}p ⋅ \frac{7}{27} ⋅ (-q) = \frac{3 ⋅ 7}{14 ⋅ 27}pq = \frac{1}{2 ⋅ 9}pq = \frac{1}{18}pq
1\frac{3}{5}x ⋅ (-\frac{15}{32}y) = \frac{8}{5}x ⋅ (-\frac{15}{32}y) = -\frac{8 ⋅ 15}{5 ⋅ 32}xy = -\frac{3}{2 ⋅ 4}xy = -\frac{3}{8}xy
Упростим выражение -1,25a ⋅ 8b, получим: -1,25 ⋅ 8 ⋅ ab = -10ab
Дано: a = -2\frac{1}{12} = -\frac{25}{12}, b = -1\frac{1}{5} = -\frac{6}{5}
-10 ⋅ (-\frac{25}{12}) ⋅ (-\frac{6}{5}) = -10 ⋅ \frac{25 ⋅ 6}{12 ⋅ 5} = -10 ⋅ \frac{5 ⋅ 1}{2 ⋅ 1} = -10 ⋅ \frac{5}{2} = -5 ⋅ 5 = -25
Ответ: -8,4b; 0,35y; -14,4cd; 0,9abc; 1/18pq; -3/8xy; -25