Вариант 3 1. Выполните действия: a) 2 1/7 : 4 1/6 * 2 1/3 = б) 6 3/7 * 3 1/3 : 1 1/7 = в) (6 1/5 - 4 1/3) : 1 1/3 = г) (7 2/3 - 5 4/5) * 2 4/5 = д) 5 4/19 * 3 4/7 + 1 15/19 : 2 7/25 = е) 2 3/11 * 7/9 + 6 8/11 : 1 1/8 = Вариант 4 1. Выполните действия: a) 5 1/3 * 2 1/4 : 4/5 = б) 1 4/11 * 3 3/7 : 3 1/7 = в) 2 2/5 : (3 2/5 - 1 11/15) = г) 1 8/9 : (3 1/6 - 1 3/4) = д) 6 3/8 * 1 7/17 - 2 3/8 : 1 1/4 + 2/5 = е) 10 - 2 1/2 : 3 3/4 + (2 1/2 - 1 1/3) * 6 =

Привет! Давай вместе решим эти примеры. Вариант 3 a) \(2 \frac{1}{7} : 4 \frac{1}{6} \cdot 2 \frac{1}{3} = \frac{15}{7} : \frac{25}{6} \cdot \frac{7}{3} = \frac{15}{7} \cdot \frac{6}{25} \cdot \frac{7}{3} = \frac{15 \cdot 6 \cdot 7}{7 \cdot 25 \cdot 3} = \frac{3 \cdot 5 \cdot 2 \cdot 3 \cdot 7}{7 \cdot 5 \cdot 5 \cdot 3} = \frac{2 \cdot 3}{5} = \frac{6}{5} = 1 \frac{1}{5}\) б) \(6 \frac{3}{7} \cdot 3 \frac{1}{3} : 1 \frac{1}{7} = \frac{45}{7} \cdot \frac{10}{3} : \frac{8}{7} = \frac{45}{7} \cdot \frac{10}{3} \cdot \frac{7}{8} = \frac{45 \cdot 10 \cdot 7}{7 \cdot 3 \cdot 8} = \frac{3 \cdot 3 \cdot 5 \cdot 2 \cdot 5 \cdot 7}{7 \cdot 3 \cdot 2 \cdot 4} = \frac{3 \cdot 5 \cdot 5}{4} = \frac{75}{4} = 18 \frac{3}{4}\) в) \((6 \frac{1}{5} - 4 \frac{1}{3}) : 1 \frac{1}{3} = (\frac{31}{5} - \frac{13}{3}) : \frac{4}{3} = (\frac{31 \cdot 3}{5 \cdot 3} - \frac{13 \cdot 5}{3 \cdot 5}) : \frac{4}{3} = (\frac{93}{15} - \frac{65}{15}) : \frac{4}{3} = \frac{28}{15} : \frac{4}{3} = \frac{28}{15} \cdot \frac{3}{4} = \frac{28 \cdot 3}{15 \cdot 4} = \frac{4 \cdot 7 \cdot 3}{3 \cdot 5 \cdot 4} = \frac{7}{5} = 1 \frac{2}{5}\) г) \((7 \frac{2}{3} - 5 \frac{4}{5}) \cdot 2 \frac{4}{5} = (\frac{23}{3} - \frac{29}{5}) \cdot \frac{14}{5} = (\frac{23 \cdot 5}{3 \cdot 5} - \frac{29 \cdot 3}{5 \cdot 3}) \cdot \frac{14}{5} = (\frac{115}{15} - \frac{87}{15}) \cdot \frac{14}{5} = \frac{28}{15} \cdot \frac{14}{5} = \frac{28 \cdot 14}{15 \cdot 5} = \frac{392}{75} = 5 \frac{17}{75}\) д) \(5 \frac{4}{19} \cdot 3 \frac{4}{7} + 1 \frac{15}{19} : 2 \frac{7}{25} = \frac{99}{19} \cdot \frac{25}{7} + \frac{34}{19} : \frac{57}{25} = \frac{99 \cdot 25}{19 \cdot 7} + \frac{34}{19} \cdot \frac{25}{57} = \frac{2475}{133} + \frac{34 \cdot 25}{19 \cdot 57} = \frac{2475}{133} + \frac{850}{1083} = \frac{2475}{133} + \frac{850}{1083} = \frac{2475 \cdot 81}{133 \cdot 81} + \frac{850 \cdot 7}{1083 \cdot 7} = \frac{200475}{10773} + \frac{5950}{10773} = \frac{206425}{10773} = 19 \frac{15298}{10773} \approx 19.16 \) е) \(2 \frac{3}{11} \cdot \frac{7}{9} + 6 \frac{8}{11} : 1 \frac{1}{8} = \frac{25}{11} \cdot \frac{7}{9} + \frac{74}{11} : \frac{9}{8} = \frac{25 \cdot 7}{11 \cdot 9} + \frac{74}{11} \cdot \frac{8}{9} = \frac{175}{99} + \frac{592}{99} = \frac{175 + 592}{99} = \frac{767}{99} = 7 \frac{74}{99}\) Вариант 4 a) \(5 \frac{1}{3} \cdot 2 \frac{1}{4} : \frac{4}{5} = \frac{16}{3} \cdot \frac{9}{4} : \frac{4}{5} = \frac{16}{3} \cdot \frac{9}{4} \cdot \frac{5}{4} = \frac{16 \cdot 9 \cdot 5}{3 \cdot 4 \cdot 4} = \frac{4 \cdot 4 \cdot 3 \cdot 3 \cdot 5}{3 \cdot 4 \cdot 4} = 3 \cdot 5 = 15\) б) \(1 \frac{4}{11} \cdot 3 \frac{3}{7} : 3 \frac{1}{7} = \frac{15}{11} \cdot \frac{24}{7} : \frac{22}{7} = \frac{15}{11} \cdot \frac{24}{7} \cdot \frac{7}{22} = \frac{15 \cdot 24 \cdot 7}{11 \cdot 7 \cdot 22} = \frac{15 \cdot 24}{11 \cdot 22} = \frac{15 \cdot 12}{11 \cdot 11} = \frac{180}{121} = 1 \frac{59}{121}\) в) \(2 \frac{2}{5} : (3 \frac{2}{5} - 1 \frac{11}{15}) = \frac{12}{5} : (\frac{17}{5} - \frac{26}{15}) = \frac{12}{5} : (\frac{17 \cdot 3}{5 \cdot 3} - \frac{26}{15}) = \frac{12}{5} : (\frac{51}{15} - \frac{26}{15}) = \frac{12}{5} : \frac{25}{15} = \frac{12}{5} : \frac{5}{3} = \frac{12}{5} \cdot \frac{3}{5} = \frac{36}{25} = 1 \frac{11}{25}\) г) \(1 \frac{8}{9} : (3 \frac{1}{6} - 1 \frac{3}{4}) = \frac{17}{9} : (\frac{19}{6} - \frac{7}{4}) = \frac{17}{9} : (\frac{19 \cdot 2}{6 \cdot 2} - \frac{7 \cdot 3}{4 \cdot 3}) = \frac{17}{9} : (\frac{38}{12} - \frac{21}{12}) = \frac{17}{9} : \frac{17}{12} = \frac{17}{9} \cdot \frac{12}{17} = \frac{12}{9} = \frac{4}{3} = 1 \frac{1}{3}\) д) \(6 \frac{3}{8} \cdot 1 \frac{7}{17} - 2 \frac{3}{8} : 1 \frac{1}{4} + \frac{2}{5} = \frac{51}{8} \cdot \frac{24}{17} - \frac{19}{8} : \frac{5}{4} + \frac{2}{5} = \frac{51 \cdot 24}{8 \cdot 17} - \frac{19}{8} \cdot \frac{4}{5} + \frac{2}{5} = \frac{3 \cdot 17 \cdot 3 \cdot 8}{8 \cdot 17} - \frac{19 \cdot 4}{8 \cdot 5} + \frac{2}{5} = 9 - \frac{19}{10} + \frac{2}{5} = 9 - \frac{19}{10} + \frac{4}{10} = 9 - \frac{15}{10} = 9 - \frac{3}{2} = 9 - 1 \frac{1}{2} = 7 \frac{1}{2}\) е) \(10 - 2 \frac{1}{2} : 3 \frac{3}{4} + (2 \frac{1}{2} - 1 \frac{1}{3}) \cdot 6 = 10 - \frac{5}{2} : \frac{15}{4} + (\frac{5}{2} - \frac{4}{3}) \cdot 6 = 10 - \frac{5}{2} \cdot \frac{4}{15} + (\frac{5 \cdot 3}{2 \cdot 3} - \frac{4 \cdot 2}{3 \cdot 2}) \cdot 6 = 10 - \frac{2}{3} + (\frac{15}{6} - \frac{8}{6}) \cdot 6 = 10 - \frac{2}{3} + \frac{7}{6} \cdot 6 = 10 - \frac{2}{3} + 7 = 17 - \frac{2}{3} = 16 \frac{1}{3}\)

Ответ: Вариант 3: a) \(1 \frac{1}{5}\), б) \(18 \frac{3}{4}\), в) \(1 \frac{2}{5}\), г) \(5 \frac{17}{75}\), д) \(19 \frac{15298}{10773}\), е) \(7 \frac{74}{99}\); Вариант 4: a) \(15\), б) \(1 \frac{59}{121}\), в) \(1 \frac{11}{25}\), г) \(1 \frac{1}{3}\), д) \(7 \frac{1}{2}\), е) \(16 \frac{1}{3}\)

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