\(\arcsin \frac{\sqrt{3}}{2} = \frac{\pi}{3}\)
\(\arccos \frac{1}{2} = \frac{\pi}{3}\)
\(\operatorname{ctg} \left(\frac{\pi}{3} + \frac{\pi}{3}\right) = \operatorname{ctg} \frac{2\pi}{3} = -\frac{1}{\sqrt{3}}\)