Вариант 2: 1) $\sqrt{50}+\sqrt{98}-\sqrt{200}$; 2) $5\sqrt{12}-2\sqrt{48}+2\sqrt{27}$; 3) $\sqrt{20}+2\sqrt{45}-3\sqrt{500}$; 4) $\sqrt{9a}+\sqrt{25a}-\sqrt{36a}$; 5) $5\sqrt{27t}-4\sqrt{48t}-2\sqrt{12t}$.

Question

Вопрос: $Фото задания: Вариант 2: 1) $\sqrt{50}+\sqrt{98}-\sqrt{200}$; 2) $5\sqrt{12}-2\sqrt{48}+2\sqrt{27}$; 3)…$ Фото задания

Accepted Answer

$\sqrt{50}+\sqrt{98}-\sqrt{200}=5\sqrt2+7\sqrt2-10\sqrt2=2\sqrt2$.
$5\sqrt{12}-2\sqrt{48}+2\sqrt{27}=10\sqrt3-8\sqrt3+6\sqrt3=8\sqrt3$.
$\sqrt{20}+2\sqrt{45}-3\sqrt{500}=2\sqrt5+6\sqrt5-30\sqrt5=-22\sqrt5$.
При $a\geq0$: $\sqrt{9a}+\sqrt{25a}-\sqrt{36a}=3\sqrt a+5\sqrt a-6\sqrt a=2\sqrt a$.
При $t\geq0$: $5\sqrt{27t}-4\sqrt{48t}-2\sqrt{12t}=15\sqrt{3t}-16\sqrt{3t}-4\sqrt{3t}=-5\sqrt{3t}$.

Ответ: 1) $2\sqrt2$; 2) $8\sqrt3$; 3) $-22\sqrt5$; 4) $2\sqrt a$; 5) $-5\sqrt{3t}$.

Вариант 2: 1) \(\sqrt{50}+\sqrt{98}-\sqrt{200}\); 2) \(5\sqrt{12}-2\sqrt{48}+2\sqrt{27}\); 3) \(\sqrt{20}+2\sqrt{45}-3\sqrt{500}\); 4) \(\sqrt{9a}+\sqrt{25a}-\sqrt{36a}\); 5) \(5\sqrt{27t}-4\sqrt{48t}-2\sqrt{12t}\).