\( \frac{16-12+3}{23} = \frac{7}{23} \)
\( (2+6) + (\frac{5}{11}+\frac{7}{11}) = 8 + \frac{12}{11} = 8 + 1\frac{1}{11} = 9\frac{1}{11} \)
\( 6\frac{5}{5} - 4\frac{4}{5} = (6-4) + (\frac{5}{5}-\frac{4}{5}) = 2 + \frac{1}{5} = 2\frac{1}{5} \)
\( 4\frac{17}{13} - 3\frac{9}{13} = (4-3) + (\frac{17}{13}-\frac{9}{13}) = 1 + \frac{8}{13} = 1\frac{8}{13} \)