Вариант 2: а) 7x − 11 = 10x + 16; б) 2 1/3 x + 2 5/12 = 1 3/4 + 3 2/9 x; в) 3/7 − 1/4 x = 5 3/7 − 4x

а) \[7x-11=10x+16\] \[7x-10x=16+11\] \[-3x=27\] \[x=-9\]

б) \[\frac{7}{3}x+\frac{29}{12}=\frac{7}{4}+\frac{29}{9}x\] \[\left(\frac{7}{3}-\frac{29}{9}\right)x=\frac{7}{4}-\frac{29}{12}\] \[-\frac{8}{9}x=-\frac{2}{3}\] \[x=\frac{3}{4}\]

в) \[\frac{3}{7}-\frac{1}{4}x=\frac{38}{7}-4x\] \[4x-\frac{1}{4}x=\frac{38}{7}-\frac{3}{7}\] \[\frac{15}{4}x=5\] \[x=\frac{4}{3}\]

Ответ: а) \(x=-9\); б) \(x=\frac{3}{4}\); в) \(x=\frac{4}{3}\).