Вопрос:

Вариант 3: 1) \(\frac{3}{8} + \frac{7}{16}\) 2) \(\frac{5}{6} + \frac{11}{18}\) 3) \(\frac{7}{11} + \frac{5}{33}\) 4) \(\frac{8}{9} + \frac{5}{18}\) 5) \(\frac{3}{5} + \frac{2}{15}\) 6) \(\frac{8}{17} + \frac{1}{34}\) 7) \(\frac{1}{4} + \frac{1}{6}\) 8) \(\frac{5}{8} + \frac{1}{10}\) 9) \(\frac{7}{9} + \frac{1}{6}\) 10) \(\frac{2}{21} + \frac{3}{14}\)

Ответ:

Вариант 3

  1. \(\frac{3}{8} + \frac{7}{16} = \frac{3 \times 2}{8 \times 2} + \frac{7}{16} = \frac{6}{16} + \frac{7}{16} = \frac{6+7}{16} = \frac{13}{16}\)

  2. \(\frac{5}{6} + \frac{11}{18} = \frac{5 \times 3}{6 \times 3} + \frac{11}{18} = \frac{15}{18} + \frac{11}{18} = \frac{15+11}{18} = \frac{26}{18} = \frac{13}{9} = 1\frac{4}{9}\)

  3. \(\frac{7}{11} + \frac{5}{33} = \frac{7 \times 3}{11 \times 3} + \frac{5}{33} = \frac{21}{33} + \frac{5}{33} = \frac{21+5}{33} = \frac{26}{33}\)

  4. \(\frac{8}{9} + \frac{5}{18} = \frac{8 \times 2}{9 \times 2} + \frac{5}{18} = \frac{16}{18} + \frac{5}{18} = \frac{16+5}{18} = \frac{21}{18} = \frac{7}{6} = 1\frac{1}{6}\)

  5. \(\frac{3}{5} + \frac{2}{15} = \frac{3 \times 3}{5 \times 3} + \frac{2}{15} = \frac{9}{15} + \frac{2}{15} = \frac{9+2}{15} = \frac{11}{15}\)

  6. \(\frac{8}{17} + \frac{1}{34} = \frac{8 \times 2}{17 \times 2} + \frac{1}{34} = \frac{16}{34} + \frac{1}{34} = \frac{16+1}{34} = \frac{17}{34} = \frac{1}{2}\)

  7. \(\frac{1}{4} + \frac{1}{6} = \frac{1 \times 3}{4 \times 3} + \frac{1 \times 2}{6 \times 2} = \frac{3}{12} + \frac{2}{12} = \frac{3+2}{12} = \frac{5}{12}\)

  8. \(\frac{5}{8} + \frac{1}{10} = \frac{5 \times 5}{8 \times 5} + \frac{1 \times 4}{10 \times 4} = \frac{25}{40} + \frac{4}{40} = \frac{25+4}{40} = \frac{29}{40}\)

  9. \(\frac{7}{9} + \frac{1}{6} = \frac{7 \times 2}{9 \times 2} + \frac{1 \times 3}{6 \times 3} = \frac{14}{18} + \frac{3}{18} = \frac{14+3}{18} = \frac{17}{18}\)

  10. \(\frac{2}{21} + \frac{3}{14} = \frac{2 \times 2}{21 \times 2} + \frac{3 \times 3}{14 \times 3} = \frac{4}{42} + \frac{9}{42} = \frac{4+9}{42} = \frac{13}{42}\)