Ответ:
а) \(1-\frac{5}{9}=\frac{4}{9}\).
б) \(4\frac{4}{15}-2\frac{9}{40}=2+\frac{32}{120}-\frac{27}{120}=2\frac{1}{24}\).
в) \(5-1\frac{4}{5}=4-\frac{4}{5}=3\frac{1}{5}\).
г) \(6\frac{7}{15}-3\frac{9}{10}=3+\frac{14}{30}-\frac{27}{30}=2\frac{17}{30}\).
д) \(5\frac{1}{20}-2\frac{1}{12}=3+\frac{3}{60}-\frac{5}{60}=2\frac{49}{60}\).
е) \(4\frac{1}{26}-3\frac{8}{39}=1+\frac{3}{78}-\frac{16}{78}=\frac{65}{78}\).
Ответ: а) \(\frac{4}{9}\); б) \(2\frac{1}{24}\); в) \(3\frac{1}{5}\); г) \(2\frac{17}{30}\); д) \(2\frac{49}{60}\); е) \(\frac{65}{78}\).
