Вариант 6
- \( x^2 = 7x + 18 \)
- \( x^2 - 7x - 18 = 0 \)
- \( D = (-7)^2 - 4 \cdot 1 \cdot (-18) = 49 + 72 = 121 \)
- \( x_1 = \frac{7 + \sqrt{121}}{2} = \frac{7 + 11}{2} = 9 \)
- \( x_2 = \frac{7 - \sqrt{121}}{2} = \frac{7 - 11}{2} = -2 \)
- \( 7x^2 + 9x + 2 = 0 \)
- \( D = 9^2 - 4 \cdot 7 \cdot 2 = 81 - 56 = 25 \)
- \( x_1 = \frac{-9 + \sqrt{25}}{2 \cdot 7} = \frac{-9 + 5}{14} = -\frac{4}{14} = -\frac{2}{7} \)
- \( x_2 = \frac{-9 - \sqrt{25}}{2 \cdot 7} = \frac{-9 - 5}{14} = -\frac{14}{14} = -1 \)
- \( x^2 - 5x + 6 = 0 \)
- \( D = (-5)^2 - 4 \cdot 1 \cdot 6 = 25 - 24 = 1 \)
- \( x_1 = \frac{5 + \sqrt{1}}{2} = \frac{5 + 1}{2} = 3 \)
- \( x_2 = \frac{5 - \sqrt{1}}{2} = \frac{5 - 1}{2} = 2 \)
Ответ: Вариант 6: x1 = 9, x2 = -2; x1 = -2/7, x2 = -1; x1 = 3, x2 = 2.