a) \(5 \frac{7}{24} + 7 \frac{5}{24} = (5 + 7) + (\frac{7}{24} + \frac{5}{24}) = 12 + \frac{12}{24} = 12 + \frac{1}{2} = 12 \frac{1}{2}\)
б) \(12 \frac{6}{7} - 5 \frac{3}{7} = (12 - 5) + (\frac{6}{7} - \frac{3}{7}) = 7 + \frac{3}{7} = 7 \frac{3}{7}\)
в) \(10 \frac{16}{27} - 6 \frac{10}{27} + 4 \frac{5}{27} = (10 - 6 + 4) + (\frac{16}{27} - \frac{10}{27} + \frac{5}{27}) = 8 + \frac{11}{27} = 8 \frac{11}{27}\)
г) \(8 \frac{4}{15} + 2 \frac{11}{15} = (8 + 2) + (\frac{4}{15} + \frac{11}{15}) = 10 + \frac{15}{15} = 10 + 1 = 11\)
д) \(4 \frac{5}{9} + 3 \frac{7}{9} = (4 + 3) + (\frac{5}{9} + \frac{7}{9}) = 7 + \frac{12}{9} = 7 + 1 \frac{3}{9} = 8 \frac{1}{3}\)
e) \(1 - \frac{14}{23} = \frac{23}{23} - \frac{14}{23} = \frac{9}{23}\)
ж) \(6 - 3 \frac{4}{9} = 5 \frac{9}{9} - 3 \frac{4}{9} = (5 - 3) + (\frac{9}{9} - \frac{4}{9}) = 2 + \frac{5}{9} = 2 \frac{5}{9}\)
з) \(9 \frac{5}{12} - 4 \frac{7}{12} = 8 \frac{17}{12} - 4 \frac{7}{12} = (8 - 4) + (\frac{17}{12} - \frac{7}{12}) = 4 + \frac{10}{12} = 4 \frac{5}{6}\)
и) \(24 \frac{11}{36} - 5 \frac{25}{36} = 23 \frac{47}{36} - 5 \frac{25}{36} = (23 - 5) + (\frac{47}{36} - \frac{25}{36}) = 18 + \frac{22}{36} = 18 \frac{11}{18}\)
Ответ: См. решение выше