2 вариант 1 CuO 2 Cu(OH)2 3 CuS 4 Cu Cl2 5 СиЅОз 6 СиЅО4 7 СиСОз 8 Си(NO3)2 9 Си з(РО4)2

Определим массовые доли элементов в соединениях.

1. CuO
   • Mr(CuO) = 64 + 16 = 80
   • w(Cu) = (64/80) * 100% = 80%
   • w(O) = (16/80) * 100% = 20%
2. Cu(OH)2
   • Mr(Cu(OH)2) = 64 + 2*(16 + 1) = 64 + 34 = 98
   • w(Cu) = (64/98) * 100% = 65.3%
   • w(O) = (32/98) * 100% = 32.7%
   • w(H) = (2/98) * 100% = 2.04%
3. CuS
   • Mr(CuS) = 64 + 32 = 96
   • w(Cu) = (64/96) * 100% = 66.67%
   • w(S) = (32/96) * 100% = 33.33%
4. CuCl2
   • Mr(CuCl2) = 64 + 2*35.5 = 64 + 71 = 135
   • w(Cu) = (64/135) * 100% = 47.4%
   • w(Cl) = (71/135) * 100% = 52.6%
5. CuSO3
   • Mr(CuSO3) = 64 + 32 + 3*16 = 64 + 32 + 48 = 144
   • w(Cu) = (64/144) * 100% = 44.4%
   • w(S) = (32/144) * 100% = 22.2%
   • w(O) = (48/144) * 100% = 33.3%
6. CuSO4
   • Mr(CuSO4) = 64 + 32 + 4*16 = 64 + 32 + 64 = 160
   • w(Cu) = (64/160) * 100% = 40%
   • w(S) = (32/160) * 100% = 20%
   • w(O) = (64/160) * 100% = 40%
7. CuCO3
   • Mr(CuCO3) = 64 + 12 + 3*16 = 64 + 12 + 48 = 124
   • w(Cu) = (64/124) * 100% = 51.6%
   • w(C) = (12/124) * 100% = 9.7%
   • w(O) = (48/124) * 100% = 38.7%
8. Cu(NO3)2
   • Mr(Cu(NO3)2) = 64 + 2*(14 + 3*16) = 64 + 2*(14 + 48) = 64 + 2*62 = 64 + 124 = 188
   • w(Cu) = (64/188) * 100% = 34%
   • w(N) = (28/188) * 100% = 14.9%
   • w(O) = (96/188) * 100% = 51.1%
9. Cu3(PO4)2
   • Mr(Cu3(PO4)2) = 3*64 + 2*(31 + 4*16) = 192 + 2*(31 + 64) = 192 + 2*95 = 192 + 190 = 382
   • w(Cu) = (192/382) * 100% = 50.3%
   • w(P) = (62/382) * 100% = 16.2%
   • w(O) = (128/382) * 100% = 33.5%

Ответ: Массовые доли определены.