а)
\[n^3 - \frac{4}{9} = (-1)^3 - \frac{4}{9} = -1 - \frac{4}{9} = -\frac{9}{9} - \frac{4}{9} = -\frac{13}{9} = -1\frac{4}{9}\]
- Если \(n = -\frac{1}{3}\), то:
\[n^3 - \frac{4}{9} = \left(-\frac{1}{3}\right)^3 - \frac{4}{9} = -\frac{1}{27} - \frac{4}{9} = -\frac{1}{27} - \frac{12}{27} = -\frac{13}{27}\]
б)
- Если \(m = \frac{6}{7}\), то:
\[4 - m^2 = 4 - \left(\frac{6}{7}\right)^2 = 4 - \frac{36}{49} = \frac{196}{49} - \frac{36}{49} = \frac{160}{49}\]
\[4 - m^2 = 4 - (-1)^2 = 4 - 1 = 3\]
\[4 - m^2 = 4 - (-0.5)^2 = 4 - 0.25 = 3.75\]
а)
\[\left(-\frac{19}{25} + \frac{2}{5} \cdot (-0.6)\right) \cdot 0.8 = \left(-\frac{19}{25} - \frac{1.2}{5}\right) \cdot 0.8 = \left(-\frac{19}{25} - \frac{6}{25}\right) \cdot 0.8 = -\frac{25}{25} \cdot 0.8 = -1 \cdot 0.8 = -0.8\]
б)
\[-9.6 \cdot \frac{5}{16} - (-3.4)^2 + 9.06 = -9.6 \cdot \frac{5}{16} - 11.56 + 9.06 = -3 \cdot 1 - 11.56 + 9.06 = -3 - 11.56 + 9.06 = -14.56 + 9.06 = -5.5\]