Решим примеры по порядку.
- 4$$\frac{13}{17}$$+5$$\frac{4}{17}$$ = (4+5)+($$\frac{13}{17}$$+$$\frac{4}{17}$$) = 9+$$\frac{13+4}{17}$$ = 9$$\frac{17}{17}$$ = 9+1=10
- 3$$\frac{8}{11}$$+2$$\frac{6}{11}$$ = (3+2)+($$\frac{8}{11}$$+$$\frac{6}{11}$$) = 5+$$\frac{8+6}{11}$$ = 5$$\frac{14}{11}$$ = 5+1$$\frac{3}{11}$$=6$$\frac{3}{11}$$
- 1-\frac{16}{21}$$ = $$\frac{21}{21}$$-$$\frac{16}{21}$$ = $$\frac{21-16}{21}$$ = $$\frac{5}{21}$$
- 5-2$$\frac{3}{8}$$ = 4$$\frac{8}{8}$$-2$$\frac{3}{8}$$ = (4-2)+($$\frac{8}{8}$$-$$\frac{3}{8}$$) = 2+$$\frac{8-3}{8}$$ = 2$$\frac{5}{8}$$
- 8$$\frac{4}{9}$$-3$$\frac{7}{9}$$ = 7$$\frac{13}{9}$$-3$$\frac{7}{9}$$ = (7-3)+($$\frac{13}{9}$$-$$\frac{7}{9}$$) = 4+$$\frac{13-7}{9}$$ = 4$$\frac{6}{9}$$ = 4$$\frac{2}{3}$$
- 12$$\frac{19}{44}$$-6$$\frac{37}{44}$$ = 11$$\frac{63}{44}$$-6$$\frac{37}{44}$$ = (11-6)+($$\frac{63}{44}$$-$$\frac{37}{44}$$) = 5+$$\frac{63-37}{44}$$ = 5$$\frac{26}{44}$$ = 5$$\frac{13}{22}$$
Решим задачу.
Миша съел - $$\frac{3}{10}$$ арбуза.
Саша съел - $$\frac{5}{10}$$ арбуза.
Наташа съела - ?
Всего арбуз - 1.
Решение:
- $$\frac{3}{10}$$+$$\frac{5}{10}$$ = $$\frac{3+5}{10}$$ = $$\frac{8}{10}$$ - съели Миша и Саша вместе.
- 1 - $$\frac{8}{10}$$ = $$\frac{10}{10}$$ - $$\frac{8}{10}$$ = $$\frac{10-8}{10}$$ = $$\frac{2}{10}$$ = $$\frac{1}{5}$$ - съела Наташа.
Ответ: 1) 10; 2) 6$$\frac{3}{11}$$; 3) $$\frac{5}{21}$$; 4) 2$$\frac{5}{8}$$; 5) 4$$\frac{2}{3}$$; 6) 5$$\frac{13}{22}$$; Наташа съела $$\frac{1}{5}$$ часть арбуза.