Верхняя часть: и) \(\frac{1}{3}+\frac{5}{6}\); к) \(8\frac{5}{40}+7\frac{10}{60}\); л) \(\frac{17}{21}-\frac{8}{15}\); м) \(13\frac{1}{22}-11\frac{3}{55}\).

1. \(\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{7}{6}=1\frac{1}{6}\).
2. \(8\frac{5}{40}+7\frac{10}{60}=8\frac{1}{8}+7\frac{1}{6}=15+\frac{7}{24}=15\frac{7}{24}\).
3. \(\frac{17}{21}-\frac{8}{15}=\frac{85}{105}-\frac{56}{105}=\frac{29}{105}\).
4. \(13\frac{1}{22}-11\frac{3}{55}=13\frac{5}{110}-11\frac{6}{110}=2-\frac{1}{110}=1\frac{109}{110}\).

Ответ: \(1\frac{1}{6};\ 15\frac{7}{24};\ \frac{29}{105};\ 1\frac{109}{110}\).