\[ \frac{36}{\sqrt{5}-1} \cdot \frac{\sqrt{5}+1}{\sqrt{5}+1} = \frac{36(\sqrt{5}+1)}{(\sqrt{5})^2 - 1^2} = \frac{36(\sqrt{5}+1)}{5 - 1} = \frac{36(\sqrt{5}+1)}{4} = 9(\sqrt{5}+1) = 9\sqrt{5} + 9 \]
\[ (9\sqrt{5} + 9) - 9\sqrt{5} \]
\[ 9\sqrt{5} + 9 - 9\sqrt{5} = 9 \]
Ответ: 9