Ответ:
Вычислим суммы:
- \(3\frac{1}{4}+5\frac{1}{5}=8+\frac{1}{4}+\frac{1}{5}=8\frac{9}{20}\).
- \(2\frac{1}{10}+6\frac{1}{6}=8+\frac{1}{10}+\frac{1}{6}=8\frac{4}{15}\).
- \(1\frac{1}{4}+7\frac{1}{6}=8+\frac{1}{4}+\frac{1}{6}=8\frac{5}{12}\).
- \(4\frac{1}{5}+4\frac{1}{6}=8+\frac{1}{5}+\frac{1}{6}=8\frac{11}{30}\).
Сравним дробные части: \(\frac{9}{20}=\frac{27}{60}\), \(\frac{4}{15}=\frac{16}{60}\), \(\frac{5}{12}=\frac{25}{60}\), \(\frac{11}{30}=\frac{22}{60}\). Наибольшая дробная часть — \(\frac{9}{20}\).
Ответ: \(3\frac{1}{4}+5\frac{1}{5}=8\frac{9}{20}\).
