Вычислим: $$5 \cdot 1\frac{2}{15} + (\frac{5}{6} - \frac{11}{2}) : 1\frac{6}{5}$$
- $$1\frac{2}{15} = \frac{15+2}{15} = \frac{17}{15}$$
- $$1\frac{6}{5} = \frac{5+6}{5} = \frac{11}{5}$$
- $$5 \cdot \frac{17}{15} = \frac{5 \cdot 17}{15} = \frac{1 \cdot 17}{3} = \frac{17}{3}$$
- $$\frac{5}{6} - \frac{11}{2} = \frac{5}{6} - \frac{11 \cdot 3}{2 \cdot 3} = \frac{5}{6} - \frac{33}{6} = \frac{5-33}{6} = \frac{-28}{6} = -\frac{14}{3}$$
- $$-\frac{14}{3} : \frac{11}{5} = -\frac{14}{3} \cdot \frac{5}{11} = -\frac{14 \cdot 5}{3 \cdot 11} = -\frac{70}{33}$$
- $$\frac{17}{3} - \frac{70}{33} = \frac{17 \cdot 11}{3 \cdot 11} - \frac{70}{33} = \frac{187}{33} - \frac{70}{33} = \frac{187 - 70}{33} = \frac{117}{33} = \frac{39}{11} = 3\frac{6}{11}$$
Ответ: $$3\frac{6}{11}$$