3) Вычисли разность: a) 1-\frac{4}{9}=\frac{9}{9}-\frac{4}{9}=\frac{5}{9} 6) 5-\frac{2}{3}=4\frac{3}{3}-\frac{2}{3}=4\frac{1}{3} B) 7-2\frac{3}{8}=6\frac{8}{8}-2\frac{3}{8}=4\frac{5}{8} г) 3\frac{2}{5}-\frac{4}{5}=2\frac{7}{5}-\frac{4}{5}=2\frac{3}{5} д) 4\frac{1}{6}-1\frac{5}{6}=3\frac{7}{6}-1\frac{5}{6}=2\frac{2}{6}=2\frac{1}{3} e) 6\frac{6}{15}-2\frac{9}{15}=5\frac{21}{15}-2\frac{9}{15}=3\frac{12}{15}=3\frac{4}{5}

Вычислим разности:

а) $$1-\frac{4}{9}=\frac{9}{9}-\frac{4}{9}=\frac{9-4}{9}=\frac{5}{9}$$

б) $$5-\frac{2}{3}=4\frac{3}{3}-\frac{2}{3}=4\frac{3-2}{3}=4\frac{1}{3}$$

в) $$7-2\frac{3}{8}=6\frac{8}{8}-2\frac{3}{8}=(6-2)+\frac{8-3}{8}=4\frac{5}{8}$$

г) $$3\frac{2}{5}-\frac{4}{5}=2\frac{7}{5}-\frac{4}{5}=2\frac{7-4}{5}=2\frac{3}{5}$$

д) $$4\frac{1}{6}-1\frac{5}{6}=3\frac{7}{6}-1\frac{5}{6}=(3-1)+\frac{7-5}{6}=2\frac{2}{6}=2\frac{1}{3}$$

е) $$6\frac{6}{15}-2\frac{9}{15}=5\frac{21}{15}-2\frac{9}{15}=(5-2)+\frac{21-9}{15}=3\frac{12}{15}=3\frac{4}{5}$$

Ответ: а) $$\frac{5}{9}$$, б) $$4\frac{1}{3}$$, в) $$4\frac{5}{8}$$, г) $$2\frac{3}{5}$$, д) $$2\frac{1}{3}$$, е) $$3\frac{4}{5}$$.