3) Вычисли разность: a) 1-\(\frac{4}{9}\)=\(\frac{9}{9}\)-\(\frac{4}{9}\)=\(\frac{5}{9}\) 6) 5-\(\frac{2}{3}\)=4\(\frac{3}{3}\)-\(\frac{2}{3}\)=4\(\frac{1}{3}\) B) 7-2\(\frac{3}{8}\)=6\(\frac{8}{8}\)-2\(\frac{3}{8}\)=4\(\frac{5}{8}\) г) 3\(\frac{2}{5}\)-\(\frac{4}{5}\)=2\(\frac{7}{5}\)-\(\frac{4}{5}\)=2\(\frac{3}{5}\) д) 4\(\frac{1}{6}\)-1\(\frac{5}{6}\)=3\(\frac{7}{6}\)-1\(\frac{5}{6}\)=2\(\frac{2}{6}\)=2\(\frac{1}{3}\) e) 6\(\frac{6}{15}\)-2\(\frac{9}{15}\)=5\(\frac{21}{15}\)-2\(\frac{9}{15}\)=3\(\frac{12}{15}\)=3\(\frac{4}{5}\)

Вычислим разности:

а) $$1-\frac{4}{9}=\frac{9}{9}-\frac{4}{9}=\frac{9-4}{9}=\frac{5}{9}$$

б) $$5-\frac{2}{3}=4\frac{3}{3}-\frac{2}{3}=4\frac{3-2}{3}=4\frac{1}{3}$$

в) $$7-2\frac{3}{8}=6\frac{8}{8}-2\frac{3}{8}=(6-2)+\frac{8-3}{8}=4\frac{5}{8}$$

г) $$3\frac{2}{5}-\frac{4}{5}=2\frac{7}{5}-\frac{4}{5}=2\frac{7-4}{5}=2\frac{3}{5}$$

д) $$4\frac{1}{6}-1\frac{5}{6}=3\frac{7}{6}-1\frac{5}{6}=(3-1)+\frac{7-5}{6}=2\frac{2}{6}=2\frac{1}{3}$$

е) $$6\frac{6}{15}-2\frac{9}{15}=5\frac{21}{15}-2\frac{9}{15}=(5-2)+\frac{21-9}{15}=3\frac{12}{15}=3\frac{4}{5}$$

Ответ: а) $$\frac{5}{9}$$, б) $$4\frac{1}{3}$$, в) $$4\frac{5}{8}$$, г) $$2\frac{3}{5}$$, д) $$2\frac{1}{3}$$, е) $$3\frac{4}{5}$$.