a) 8-6\frac{11}{10} = \frac{8 \cdot 10}{10} - \frac{6 \cdot 10 + 11}{10} = \frac{80}{10} - \frac{60 + 11}{10} = \frac{80}{10} - \frac{71}{10} = \frac{80 - 71}{10} = \frac{9}{10}
в) 10-\frac{6}{15}-9\frac{1}{15} = 10 - \frac{6}{15} - \frac{9 \cdot 15 + 1}{15} = \frac{10 \cdot 15}{15} - \frac{6}{15} - \frac{135 + 1}{15} = \frac{150}{15} - \frac{6}{15} - \frac{136}{15} = \frac{150 - 6 - 136}{15} = \frac{150 - 142}{15} = \frac{8}{15}
д) 9\frac{10}{17}-3\frac{6}{17} = \frac{9 \cdot 17 + 10}{17} - \frac{3 \cdot 17 + 6}{17} = \frac{153 + 10}{17} - \frac{51 + 6}{17} = \frac{163}{17} - \frac{57}{17} = \frac{163 - 57}{17} = \frac{106}{17} = 6\frac{4}{17}
Ответ: a) \frac{9}{10}; в) \frac{8}{15}; д) 6\frac{4}{17}