Вычислить: 1) [((15/28 − 11/36) · 21/29 + 6 6/7 : 16/21)] : 16 1/2; 2) [((4 5/7 − 1 11/14) · 4 2/3 + (3 2/9 − 1 5/6) · 18/25)] : 2 3/4; 3) 9/40 · [7 5/7 : 3 3/5 − (53/56 − 29/35) : 33/40]; 4) [(5 5/9 − 7/18) : 35 + (40/63 − 8/21) : 20 + (83/90 − 41/50) : 2] · 35.

Question

Вопрос:

Вычислить: 1) [((15/28 − 11/36) · 21/29 + 6 6/7 : 16/21)] : 16 1/2; 2) [((4 5/7 − 1 11/14) · 4 2/3 + (3 2/9 − 1 5/6) · 18/25)] : 2 3/4; 3) 9/40 · [7 5/7 : 3 3/5 − (53/56 − 29/35) : 33/40]; 4) [(5 5/9 − 7/18) : 35 + (40/63 − 8/21) : 20 + (83/90 − 41/50) : 2] · 35.

Ответ:

ФИО:Телефон:Емаил:Полное описание сути нарушения прав (почему распространение данной информации запрещено Правообладателем):

Accepted Answer

\[\left[\left(\frac{15}{28}-\frac{11}{36}\right)\cdot\frac{21}{29}+6\frac{6}{7}:\frac{16}{21}\right]:16\frac{1}{2}\]
\[\frac{15}{28}-\frac{11}{36}=\frac{5}{18},\quad \frac{5}{18}\cdot\frac{21}{29}=\frac{35}{174},\quad 6\frac{6}{7}:\frac{16}{21}=\frac{48}{7}\cdot\frac{21}{16}=9.\]
\[\left(9+\frac{35}{174}\right):\frac{33}{2}=\frac{1601}{174}\cdot\frac{2}{33}=\frac{1601}{2871}.\]
Ответ: \(\frac{1601}{2871}\).
\[\left[\left(4\frac{5}{7}-1\frac{11}{14}\right)\cdot4\frac{2}{3}+\left(3\frac{2}{9}-1\frac{5}{6}\right)\cdot\frac{18}{25}\right]:2\frac{3}{4}\]
\[4\frac{5}{7}-1\frac{11}{14}=\frac{33}{7}-\frac{25}{14}=\frac{41}{14},\quad \frac{41}{14}\cdot\frac{14}{3}=\frac{41}{3}.\]
\[3\frac{2}{9}-1\frac{5}{6}=\frac{29}{9}-\frac{11}{6}=\frac{25}{18},\quad \frac{25}{18}\cdot\frac{18}{25}=1.\]
\[\left(\frac{41}{3}+1\right):\frac{11}{4}=\frac{44}{3}\cdot\frac{4}{11}=\frac{16}{3}.\]
Ответ: \(\frac{16}{3}\).
\[\frac{9}{40}\left[7\frac{5}{7}:3\frac{3}{5}-\left(\frac{53}{56}-\frac{29}{35}\right):\frac{33}{40}\right]\]
\[7\frac{5}{7}:3\frac{3}{5}=\frac{54}{7}:\frac{18}{5}=\frac{15}{7}.\]
\[\frac{53}{56}-\frac{29}{35}=\frac{53}{56}-\frac{232}{280}=\frac{33}{280},\quad \frac{33}{280}:\frac{33}{40}=\frac{1}{7}.\]
\[\frac{9}{40}\left(\frac{15}{7}-\frac{1}{7}\right)=\frac{9}{40}\cdot2=\frac{9}{20}.\]
Ответ: \(\frac{9}{20}\).
\[\left[\left(5\frac{5}{9}-\frac{7}{18}\right):35+\left(\frac{40}{63}-\frac{8}{21}\right):20+\left(\frac{83}{90}-\frac{41}{50}\right):2\right]\cdot35\]
\[5\frac{5}{9}-\frac{7}{18}=\frac{47}{9}-\frac{7}{18}=\frac{29}{6},\quad \frac{29}{6}:35=\frac{29}{210}.\]
\[\frac{40}{63}-\frac{8}{21}=\frac{16}{63},\quad \frac{16}{63}:20=\frac{4}{315}.\]
\[\frac{83}{90}-\frac{41}{50}=\frac{62}{225},\quad \frac{62}{225}:2=\frac{31}{225}.\]
\[35\left(\frac{29}{210}+\frac{4}{315}+\frac{31}{225}\right)=35\cdot\frac{2371}{14175}=\frac{2371}{405}.\]
Ответ: \(\frac{2371}{405}\).