Вычислить: 9^(1/2); 36^(-1/2); 2·125^(-1/3).

1. \(9^{1/2}=\sqrt{9}=3\).

2. \(36^{-1/2}=\frac{1}{36^{1/2}}=\frac{1}{\sqrt{36}}=\frac{1}{6}\).

3. \(2\cdot125^{-1/3}=2\cdot\frac{1}{\sqrt[3]{125}}=2\cdot\frac{1}{5}=\frac{2}{5}\).

Ответ: 3; \(\frac{1}{6}\); \(\frac{2}{5}\).