8.Вычислите:$$\frac{29}{4}:5\frac{4}{5}-\frac{3}{4} \cdot (3-1\frac{19}{30})$$

$$\frac{29}{4}:5\frac{4}{5}-\frac{3}{4} \cdot (3-1\frac{19}{30})=\frac{29}{4}:\frac{29}{5}-\frac{3}{4} \cdot (3-\frac{49}{30})=\frac{29}{4} \cdot \frac{5}{29}-\frac{3}{4} \cdot (\frac{3 \cdot 30}{30}-\frac{49}{30})=\frac{5}{4}-\frac{3}{4} \cdot (\frac{90}{30}-\frac{49}{30})=\frac{5}{4}-\frac{3}{4} \cdot \frac{41}{30}=\frac{5}{4}-\frac{3 \cdot 41}{4 \cdot 30}=\frac{5}{4}-\frac{123}{120}=\frac{5 \cdot 30}{4 \cdot 30}-\frac{123}{120}=\frac{150}{120}-\frac{123}{120}=\frac{27}{120}=\frac{9}{40}$$

Ответ:$$\frac{9}{40}$$