1. Вычислите : 1)23-42 2)(5-3)4 3)(1/3)-3 4) 72-53 5) 26+14 6)-4⋅(-2/3)3

1) $$2^3 \cdot 2^{-4} = 2^{3-4} = 2^{-1} = \frac{1}{2}$$

2) $$(5-3)^4 = 2^4 = 16$$

3) $$(\frac{1}{3})^{-3} = 3^3 = 27$$

4) $$7^2 \cdot 5^{-3} = 49 \cdot \frac{1}{125} = \frac{49}{125} = 0.392$$

5) $$2^6 + 1^4 = 64 + 1 = 65$$

6) $$-4 \cdot (-\frac{2}{3})^3 = -4 \cdot (-\frac{8}{27}) = \frac{32}{27} = 1 \frac{5}{27}$$

Ответ: 1) 1/2; 2) 16; 3) 27; 4) 49/125; 5) 65; 6) 32/27