- \(4\frac{2}{35}\cdot7=\frac{142}{35}\cdot7=\frac{142}{5}=28\frac{2}{5}\).
- \(\frac{4}{27}\cdot10=\frac{40}{27}=1\frac{13}{27}\).
- \(1\frac{3}{14}\cdot5=\frac{17}{14}\cdot5=\frac{85}{14}=6\frac{1}{14}\).
- \(7\frac{1}{9}\cdot6=\frac{64}{9}\cdot6=\frac{128}{3}=42\frac{2}{3}\).
- \(11\frac{1}{8}\cdot7=\frac{89}{8}\cdot7=\frac{623}{8}=77\frac{7}{8}\).
- \(\frac{7}{8}\cdot32=7\cdot4=28\).
- \(12\frac{5}{121}\cdot4=\frac{1457}{121}\cdot4=\frac{5828}{121}=48\frac{20}{121}\).
Ответ: \(28\frac{2}{5};\ 1\frac{13}{27};\ 6\frac{1}{14};\ 42\frac{2}{3};\ 77\frac{7}{8};\ 28;\ 48\frac{20}{121}\).