Вычислите: 1) $\left(\frac{17}{10}-\frac{1}{20}\right)\cdot\frac{2}{15}$; 2) $\left(\frac{5}{22}-\frac{8}{11}\right)\cdot\frac{11}{5}$; 3) $\left(\frac{5}{26}-\frac{3}{25}\right)\cdot\frac{13}{2}$; 4) $\left(\frac{10}{13}+\frac{15}{4}\right)\cdot\frac{26}{5}$; 5) $\left(\frac{17}{26}+\frac{11}{13}\right)\cdot\frac{17}{6}$; 6) $\left(\frac{11}{12}+\frac{11}{20}\right)\cdot\frac{15}{8}$; 7) $\left(\frac{3}{4}-\frac{1}{6}\right)\cdot3$; 8) $\left(\frac{2}{5}+\frac{13}{15}\right)\cdot6$; 9) $\left(\frac{3}{8}-\frac{1}{20}\right)\cdot10$.

Question

Вычислите: 1) $\left(\frac{17}{10}-\frac{1}{20}\right)\cdot\frac{2}{15}$; 2) $\left(\frac{5}{22}-\frac{8}{11}\right)\cdot\frac{11}{5}$; 3) $\left(\frac{5}{26}-\frac{3}{25}\right)\cdot\frac{13}{2}$; 4) $\left(\frac{10}{13}+\frac{15}{4}\right)\cdot\frac{26}{5}$; 5) $\left(\frac{17}{26}+\frac{11}{13}\right)\cdot\frac{17}{6}$; 6) $\left(\frac{11}{12}+\frac{11}{20}\right)\cdot\frac{15}{8}$; 7) $\left(\frac{3}{4}-\frac{1}{6}\right)\cdot3$; 8) $\left(\frac{2}{5}+\frac{13}{15}\right)\cdot6$; 9) $\left(\frac{3}{8}-\frac{1}{20}\right)\cdot10$.

$Фото задания: Вычислите: 1) $\left(\frac{17}{10}-\frac{1}{20}\right)\cdot\frac{2}{15}$; 2)…$ Фото задания

Accepted Answer

$\left(\frac{17}{10}-\frac{1}{20}\right)\cdot\frac{2}{15}=\left(\frac{34}{20}-\frac{1}{20}\right)\cdot\frac{2}{15}=\frac{33}{20}\cdot\frac{2}{15}=\frac{11}{50}$.
$\left(\frac{5}{22}-\frac{8}{11}\right)\cdot\frac{11}{5}=\left(\frac{5}{22}-\frac{16}{22}\right)\cdot\frac{11}{5}=-\frac{1}{2}\cdot\frac{11}{5}=-\frac{11}{10}$.
$\left(\frac{5}{26}-\frac{3}{25}\right)\cdot\frac{13}{2}=\frac{125-78}{650}\cdot\frac{13}{2}=\frac{47}{650}\cdot\frac{13}{2}=\frac{611}{1300}$.
$\left(\frac{10}{13}+\frac{15}{4}\right)\cdot\frac{26}{5}=\frac{40+195}{52}\cdot\frac{26}{5}=\frac{235}{52}\cdot\frac{26}{5}=\frac{47}{2}$.
$\left(\frac{17}{26}+\frac{11}{13}\right)\cdot\frac{17}{6}=\left(\frac{17}{26}+\frac{22}{26}\right)\cdot\frac{17}{6}=\frac{3}{2}\cdot\frac{17}{6}=\frac{17}{4}$.
$\left(\frac{11}{12}+\frac{11}{20}\right)\cdot\frac{15}{8}=\left(\frac{55}{60}+\frac{33}{60}\right)\cdot\frac{15}{8}=\frac{22}{15}\cdot\frac{15}{8}=\frac{11}{4}$.
$\left(\frac{3}{4}-\frac{1}{6}\right)\cdot3=\left(\frac{9}{12}-\frac{2}{12}\right)\cdot3=\frac{7}{12}\cdot3=\frac{7}{4}$.
$\left(\frac{2}{5}+\frac{13}{15}\right)\cdot6=\left(\frac{6}{15}+\frac{13}{15}\right)\cdot6=\frac{19}{15}\cdot6=\frac{38}{5}$.
$\left(\frac{3}{8}-\frac{1}{20}\right)\cdot10=\left(\frac{15}{40}-\frac{2}{40}\right)\cdot10=\frac{13}{40}\cdot10=\frac{13}{4}$.

Ответ: 1) $\frac{11}{50}$; 2) $-\frac{11}{10}$; 3) $\frac{611}{1300}$; 4) $\frac{47}{2}$; 5) $\frac{17}{4}$; 6) $\frac{11}{4}$; 7) $\frac{7}{4}$; 8) $\frac{38}{5}$; 9) $\frac{13}{4}$.