\( 4\frac{1}{3} = \frac{4 \cdot 3 + 1}{3} = \frac{13}{3} \)
\( 2\frac{1}{13} = \frac{2 \cdot 13 + 1}{13} = \frac{27}{13} \)
\( \frac{13}{3} \times \frac{27}{13} \)
\( \frac{\cancel{13}}{\cancel{3}^1} \times \frac{\cancel{27}^9}{\cancel{13}} = \frac{1}{1} \times \frac{9}{1} = 9 \)
Ответ: 9