1) a) $$3^{-2} = \frac{1}{3^2} = \frac{1}{9}$$
б) $$(-5)^{-2} = \frac{1}{(-5)^2} = \frac{1}{25}$$
в) $$(-6)^{-1} = \frac{1}{-6} = -\frac{1}{6}$$
г) $$-4 \cdot (-2)^{-3} = -4 \cdot \frac{1}{(-2)^3} = -4 \cdot \frac{1}{-8} = \frac{4}{8} = \frac{1}{2}$$
2) a) $$(\frac{1}{3})^{-1} = \frac{1}{\frac{1}{3}} = 3$$
б) $$(\frac{2}{5})^{-2} = (\frac{5}{2})^{2} = \frac{25}{4} = 6\frac{1}{4}$$
в) $$(-0,1)^{-4} = (\frac{-1}{10})^{-4} = (-10)^4 = 10000$$
г) $$(2\frac{1}{3})^{-3} = (\frac{7}{3})^{-3} = (\frac{3}{7})^{3} = \frac{27}{343}$$
3) a) $$8^{-1} + 6^{-2} = \frac{1}{8} + \frac{1}{36} = \frac{9}{72} + \frac{2}{72} = \frac{11}{72}$$
б) $$2,4^{-1} + 5^0 = (\frac{24}{10})^{-1} + 1 = \frac{10}{24} + 1 = \frac{5}{12} + 1 = \frac{17}{12} = 1\frac{5}{12}$$
в) $$1453 \cdot 0,1^{-3} = 1453 \cdot (\frac{1}{10})^{-3} = 1453 \cdot 10^3 = 1453000$$
г) $$18 - (\frac{1}{5})^{-2} = 18 - (5)^{2} = 18 - 25 = -7$$