Вычислите: а) 2 1/7 · (2 1/4 : 3 6/7); б) (1 2/9 + 1 5/9) · 1 4/5; в) (7 1/3 − 5 1/6) : 3 1/3; г) (2 2/15 − 1 2/5) · 6 1/4; д) (2 2/3 + 1 5/6) : 4 1/2; е) (7 1/8 − 6 3/5) : 4 1/5.

1. Переведём смешанные числа в неправильные дроби:

   \(2\frac{1}{7}=\frac{15}{7}\), \(2\frac{1}{4}=\frac{9}{4}\), \(3\frac{6}{7}=\frac{27}{7}\).

   \(\frac{15}{7}\cdot\left(\frac{9}{4}:\frac{27}{7}\right)=\frac{15}{7}\cdot\frac{9}{4}\cdot\frac{7}{27}=\frac{5}{4}=1\frac{1}{4}\).

2. \(1\frac{2}{9}+1\frac{5}{9}=\frac{11}{9}+\frac{14}{9}=\frac{25}{9}\).

   \(\frac{25}{9}\cdot1\frac{4}{5}=\frac{25}{9}\cdot\frac{9}{5}=5\).

3. \(7\frac{1}{3}-5\frac{1}{6}=\frac{22}{3}-\frac{31}{6}=\frac{13}{6}\).

   \(\frac{13}{6}:3\frac{1}{3}=\frac{13}{6}:\frac{10}{3}=\frac{13}{6}\cdot\frac{3}{10}=\frac{13}{20}\).

4. \(2\frac{2}{15}-1\frac{2}{5}=\frac{32}{15}-\frac{21}{15}=\frac{11}{15}\).

   \(\frac{11}{15}\cdot6\frac{1}{4}=\frac{11}{15}\cdot\frac{25}{4}=\frac{55}{12}=4\frac{7}{12}\).

5. \(2\frac{2}{3}+1\frac{5}{6}=\frac{8}{3}+\frac{11}{6}=\frac{27}{6}=\frac{9}{2}\).

   \(\frac{9}{2}:4\frac{1}{2}=\frac{9}{2}:\frac{9}{2}=1\).

6. \(7\frac{1}{8}-6\frac{3}{5}=\frac{57}{8}-\frac{33}{5}=\frac{21}{40}\).

   \(\frac{21}{40}:4\frac{1}{5}=\frac{21}{40}:\frac{21}{5}=\frac{21}{40}\cdot\frac{5}{21}=\frac{1}{8}\).

Ответ: а) \(1\frac{1}{4}\); б) \(5\); в) \(\frac{13}{20}\); г) \(4\frac{7}{12}\); д) \(1\); е) \(\frac{1}{8}\).